figure(1)
plot(freq, V, 'linewidth', [2])
set(gca,'fontsize',[14])
xlabel('Frequency [GHz]')
ylabel('Voltage [V]')
Keep forgetting this again and again.
Now will have it always available here.
Monday, November 8, 2010
Wednesday, October 6, 2010
Balanis - Antenna 3rd Edition - Problem 2.11
a) Do = 4; in dB :: Do = 6.0206 dB
HPBW(θ) = 120o, HPBW(φ) = 120o
b) Do = 5.093; in dB :: Do = 7.0697 dB
HPBW(θ) = 120o, HPBW(φ) = 90o
c) Do = 6; in dB :: Do = 7.7815dB
HPBW(θ) = 120o, HPBW(φ) = 74.93o
d) Do = 4.7124; in dB :: Do = 6.7324 dB
HPBW(θ) = 90o, HPBW(φ) = 120o
e) Do = 6; in dB :: Do = 7.7815 dB
HPBW(θ) = 90o, HPBW(φ) = 90o
f) Do = 7.0686; in dB :: Do = 8.4933 dB
HPBW(θ) = 90o, HPBW(φ) = 74.93o
HPBW(θ) = 120o, HPBW(φ) = 120o
b) Do = 5.093; in dB :: Do = 7.0697 dB
HPBW(θ) = 120o, HPBW(φ) = 90o
c) Do = 6; in dB :: Do = 7.7815dB
HPBW(θ) = 120o, HPBW(φ) = 74.93o
d) Do = 4.7124; in dB :: Do = 6.7324 dB
HPBW(θ) = 90o, HPBW(φ) = 120o
e) Do = 6; in dB :: Do = 7.7815 dB
HPBW(θ) = 90o, HPBW(φ) = 90o
f) Do = 7.0686; in dB :: Do = 8.4933 dB
HPBW(θ) = 90o, HPBW(φ) = 74.93o
How to calculate Half Power Beamwidth
4 Steps procedure:
1) Normalize U
2) Find θMAX
3) Set U = 0.5, solve for θ
4) Substract 3) from 2) and multiply by 2
1) Normalize U
2) Find θMAX
3) Set U = 0.5, solve for θ
4) Substract 3) from 2) and multiply by 2
Balanis - Antenna 3rd Edition - Problem 2.4
a) HPBW = 2.09 rad
b) HPBW = 1.57 rad
c) HPBW = 1.047 rad
d) HPBW = 0.785 rad
e) HPBW = 0.698 rad
f) HPBW = 0.523 rad
b) HPBW = 1.57 rad
c) HPBW = 1.047 rad
d) HPBW = 0.785 rad
e) HPBW = 0.698 rad
f) HPBW = 0.523 rad
Labels:
Antenna,
Balanis,
Chapter 2,
half power beamwidth,
HPBW
Balanis - Antenna 3rd Edition - Problem 2.3
a) 0.03315 âr (W/m2)
b) 4.16 KW
b) 4.16 KW
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