Wednesday, October 6, 2010

Balanis - Antenna 3rd Edition - Problem 2.11

a) Do = 4; in dB :: Do = 6.0206 dB
HPBW(θ) = 120o, HPBW(φ) = 120o

b) Do = 5.093; in dB :: Do = 7.0697 dB
HPBW(θ) = 120o, HPBW(φ) = 90o

c) Do = 6; in dB :: Do = 7.7815dB
HPBW(θ) = 120o, HPBW(φ) = 74.93o

d) Do = 4.7124; in dB :: Do = 6.7324 dB
HPBW(θ) = 90o, HPBW(φ) = 120o

e) Do = 6; in dB :: Do = 7.7815 dB
HPBW(θ) = 90o, HPBW(φ) = 90o

f) Do = 7.0686; in dB :: Do = 8.4933 dB
HPBW(θ) = 90o, HPBW(φ) = 74.93o

How to calculate Half Power Beamwidth

4 Steps procedure:

        1) Normalize U

        2) Find θMAX

        3) Set U = 0.5, solve for θ

        4) Substract 3) from 2) and multiply by 2

Balanis - Antenna 3rd Edition - Problem 2.4

a) HPBW = 2.09 rad

b) HPBW = 1.57 rad

c) HPBW = 1.047 rad

d) HPBW = 0.785 rad

e) HPBW = 0.698 rad

f) HPBW = 0.523 rad

Balanis - Antenna 3rd Edition - Problem 2.3

a) 0.03315 âr (W/m2)

b) 4.16 KW
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